Robot-Framework框架系统关键字之断言

准备数据
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# 三个list变量:list_a、list_b、list_c;
@{list_a} create list 1 a ${21} 21 12
@{list_b} set variable 1.0 a ${21} 21 21
@{list_c} create list
# 两个scalar变量:string和name
${string} set variable taoyi is in hangzhou
${name} set variable ty
断言实例
  1. should containshould not containshould contain x times

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    should contain    ${list_b}    1.0
    should not contain ${list_b} 1
    should contain x times ${list_b} 21 2
    # 变量${list_b}包含对象1.0而不包含对象1,且对象21在变量${lst_b}出现了两次
  2. should be emptyshould not be empty

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    should be empty    ${list_c}
    should not be empty ${list_a}
    # 变量${list_c}没有赋值,所以为空;相反,变量${list_a}有赋初始值,故为非空
  3. should be equalshould not be equal

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    should be equal    ${list_a[1]}    ${list_b[1]}
    should not be equal ${list_a} ${list_b}
    # ${list_a[1]}=a,${list_b[1]}=a故两个对象相等;而${list_a}和${list_b}有元素不一致,这两个对象不相等
  4. should be equal as numbersshould not be equal as numbers

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    should be equal as numbers    ${list_b[0]}    1.0000
    should not be equal as number ${list_b[0]} 1.1
    # ${list_b[0]}=1,忽略精度,故与1.0000相等;而即使是忽略精度,1与1.1还是不相等的
  5. should be equal as integersshould not be equal as integers

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    should be equal as integers    ${list_a[3]}    ${list_b[3]}
    should not be equal as integers ${list_a[4]} ${list_b[4]}
    # ${list_a[3]}=21,${list_b[3]}=21,而系统默认为字符串格式的“21”,故需要转化为整数类型,转化为整数后两个对象相等
    # ${list_a[4]}=12,${list_b[4]}=21,即使转化为整数后两个对象依旧是不相等
  6. should be equal as stringsshould not be equal as strings

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    should be equal as strings    ${list_a[2]}    ${list_b[2]}
    should not be equal as strings ${list_a[0]} ${list_b[0]}
    # ${list_a[2]}=${21},${list_b[2]}=${21},而均为数值型的21,故需要转化为字符串类型,转化为字符串后两个对象相等
  7. should be trueshould not be true

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    should be true    ${list_a[0]} < 10
    should not be true ${list_a[0]} < 1
    # ${list_a[0]}=1(字符串类型),其ASCII值比字符串10的ASCII值小
  8. should start withshould not start with

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    should start with    ${string}    tao
    should not start with ${string} h
    # ${string}="taoyi is in hangzhou"是以sha开头,而非以h开头
  9. should end withshould not end with

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    should end with    ${string}    hangzhou
    should not end with ${string} taoyi
    # ${string}="taoyi is in hangzhou"是以hangzhou结尾,而非以taoyi结尾
  10. should matchshould not match

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    should match    ${name}    t?
    should not match ${string} h?*
    # 模式匹配和shell中的通配符类似,它区分大小写,'*'匹配0~无穷多个字符,“?”单个字符
    # ${name}=ty,由以t开头的两个字母组成
  11. should match regexpshould not match regexp

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    should match regexp    ${name}    ^\\w{2}$
    should not match regexp ${name} ^\\d{2}$
    # 反斜杠在测试数据是转义字符,因此模式中要使用双重转义;'^'和'$'字符可以用来表示字符串的开头和结尾
    # ${name}=ty,是有两个字母--w{2}组成,而不是由两个数字--d{2}组成

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